Solution: Simplify $ p_n = \frac{n}{n(n^2 + 2)} = \frac{1}{n^2 + 2} $. As $ n \to \infty $, $ n^2 + 2 \to \infty $, so $ \lim_{n \to \infty} p_n = \boxed{0} $.

Sun, 03 May 2026 09:00:17 +0000

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