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📅 May 4, 2026 👤 scraface

May 04, 2026

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We solve this system step by step. Subtract consecutive equations:
Now subtract Eq 1 from Eq 2:
Subtract Eq 2 from Eq 3:
Subtract (A) from (B):
Substitute $ a = 0 $ into (A): $ 6(0) + b = 2 \Rightarrow b = 2 $.
Substitute $ a = 0, b = 2 $ into Eq 1:
7(0) + 3(2) + c = 7 \Rightarrow 6 + c = 7 \Rightarrow c = 1.
Now use $ p(1) $: $ 0 + 2 + 1 + d = 3 \Rightarrow d = 0 $.
Thus, $ p(x) = 2x^2 + x $. Then $ p(0) = 0 $.
But wait—this is quadratic, but the problem states $ p(x) $ is cubic....

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