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roger klotz doug funnie - AdVision eCommerce

📅 May 4, 2026 👤 scraface

May 04, 2026

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📌 Next, we find the smallest four-digit number divisible by 391. A four-digit number starts at 1000, so we divide 1000 by 391:

📌 We round up to the next whole number, which is 3. Therefore, the smallest four-digit number divisible by 391 is:

📌 Next, find the remainder when 8104 is divided by 11. We use the divisibility rule for 11, which involves alternating sums of digits:

📌 Since 3 is the alternating sum, we find the remainder by dividing 3 by 11:

📌 Divide 9876 by 1234 and find the remainder:

📌 Now, divide 1234 by the remainder 4:

📌 Solution: The sequence of dosages forms an arithmetic progression with first term $ a = 2 $, common difference $ d = 3 $, and last term $ l = 200 $. Using the formula for the $ n $-th term of an arithmetic sequence:

📌 Solution: The sequence is arithmetic with first term $ a = 5 $, common difference $ d = 6 $, and last term $ l = 299 $. Using the formula for the $ n $-th term:

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