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📰 R = a + rac{1}{a} - 2. 📰 Define $ f(a) = a + rac{1}{a} - 2 $ for $ a > 1 $. By AM-GM, $ a + rac{1}{a} \geq 2 $, with equality at $ a = 1 $. But $ a > 1 $, so $ f(a) > 0 $. However, as $ a o 1^+ $, $ f(a) o 0^+ $. The minimum value is not attained, but we seek the infimum. Since $ f(a) $ increases for $ a > 1 $, the expression approaches 0 as $ p o q^+ $, but never reaches it. However, we analyze the original expression algebraically: 📰 R = rac{(p+q)^2 + (p-q)^2}{(p-q)(p+q)} - 2 = rac{p^2 + 2pq + q^2 + p^2 - 2pq + q^2}{p^2 - q^2} - 2 = rac{2p^2 + 2q^2}{p^2 - q^2} - 2. 📰 Grovex Crypto Exchange The Hidden Gem Disrupting The Marketstart Trading Today 7211998 📰 The Trauma Behind Ben Skywalkers Transformation Why Youll Never Forget Him 3247840 📰 Green Lantern Female Characters 2763862 📰 Barry Weisss Hidden 100M Net Worth The Truth Behind His Island Life Richness 9734749 📰 How Long Is Chicken Good In The Refrigerator 8467746 📰 Escape From Duckov 9938328 📰 The Ultimate Basketball Video Game Thats Taking The World By Stormstop Watching And Play 2808338 📰 3 The Htz Stock Phenomenon Experts Say Its The Next Mega Billion Dollar 776795 📰 Verizon On Coburg Road 1611711 📰 Gen Stock Alert You Wont Believe These Hidden Profits Waiting To Be Claimed 764432 📰 Otoro 8738274 📰 Heart Shaped Uterus 2352676 📰 Lorenas Maplewood New Jersey 3615150 📰 You Wont Believe What Secret Messages Hide In Every David Lynch Film 5741965 📰 Best Games With Storylines 4868519